Fun with templates
Manu
turkeyman at gmail.com
Sat Jul 6 03:24:41 PDT 2013
On 6 July 2013 18:23, Namespace <rswhite4 at googlemail.com> wrote:
> That doesn't do what I want at all. The signature is still f(T) not
>> f(Unqual!T).
>>
>
> For non-const, const and immutable inout would do it.
>
> void f(T)(inout T var)
>
Not if there's more than 1 argument, and 'inout T' is still not 'T'.
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