AA literals/initialisation

[TheFlyingFiddle]

On Monday, 11 November 2013 at 12:14:10 UTC, Jonathan M Davis 
wrote:
> Every time you use an enum, it's replaced with its value. So, 
> if an enum is an
> AA, then that literal is copy-pasted everywhere that the enum 
> is used. So, it
> would almost certainly be foolish to use it anywhere other than 
> to assign to a
> variable (and then all of the operations are done on the 
> variable). Really,
> having an enum that's an AA is almost certainly a foolish thing 
> to do. It's
> one case where the behavior of enums doesn't help and 
> definitely hurts.
>
> - Jonathan M Davis

I have found it to be kind of usefull atleast when i'm only using 
the AA at compiletime. Like a simple vector swizzle like the code 
below. I store rgba/xyzw characters in the table with diffrent 
offsets into a static array.

Vector!(s.length, T) opDispatch(string s)()
	if(s.length > 1)
{	
     Vector!(s.length, T) res;
     foreach(i; staticIota!(0, s.length)) {
	enum offset = swizzleTable[s[i]];
	res.data[i] = data[offset];
     }
     return res;
}

However with your statement above i'm now a little worried does 
this mean that the line enum offset = swizzleTable[s[i]]; will 
not be able to pick the correct constant at compiletime? And will 
instead do some runtime AA hash lookup?