scope escaping

[Adam D. Ruppe]

On Thursday, 6 February 2014 at 20:17:25 UTC, Benjamin Thaut 
wrote:
> foo([1 2 3 4]); // allocates the array literal on the stack, 
> because it is scoped.

Absolutely. In fact, generically, any scope item could be moved 
to the stack. We were just discussing in the chat room how scope 
= stack allocation and scope = don't escape the reference 
actually go hand in hand; they are not two separate features, 
stack allocation is an optimization enabled by the restriction... 
and the restriction is required by the optimization to maintain 
memory safety.