Why can't a method be virtual AND static at the same time?

[Steven Schveighoffer]

On Wed, 29 Jan 2014 08:30:53 -0500, Martin Cejp <minexew at gmail.com> wrote:

> This is a feature I've always missed in C++. Consider the code
> below:
>
> import std.stdio;
>
> interface Logger {
> 	void print(string msg);
> }
>
> class ConsoleLogger : Logger {
> 	static override void print(string msg) {
> 		writeln(msg);
> 	}
> }
>
> void main() {
> 	Logger logger = new ConsoleLogger;
> 	
> 	ConsoleLogger.print("Hello, World!");
> }
>
> Such definition of ConsoleLogger fails to compile. I don't see
> any drawbacks to allowing this though, except the compiler would
> probably have to generate 2 methods internally.
> The way it is now, you have to either define each method twice or
> always create an instance.
> Or am I missing an obvious solution?

Interface Logger {
      final void print(string msg) { printImpl(msg); }
      void printImpl(string msg);
}

class ConsoleLogger : Logger {
      static void print(string msg) {
          writeln(msg);
      }

      override void printImpl(string msg) {
          print(msg);
      }
}

The issue you have is with the naming, you can't overload a virtual  
function with a static one. A static function call is a different call  
than a virtual one. You can't mix the two.

-Steve