Bug in mixins?
Frustrated
Frustrated at nowhere.com
Thu Mar 6 22:23:57 PST 2014
Can someone check this out? The best I can acertain is that the
mixin template isn't adding the generated functions because it
thinks they are already in the class.
i.e., the code generates the following methods
@property iButton button(iButton b)
@property iBorder border(iBorder b)
and the class contains the methods
@property WindowsButton button()
@property WindowsButton button(WindowsButton b)
and the template mixin simply doesn't add the generic methods.
(simply because mixing the string mixin directly works, wrapping
it in a mixin template does not)
Using that I created a MWE:
http://dpaste.dzfl.pl/6f64e49aba95
import std.stdio, std.cstream;
// mixin template used to wrap the string mixin
mixin template C() { mixin(B); }
// eponymously named template used as a string mixin to generate
the function
template B()
{
string B() { return "void foo(iA a) { writeln(`Generic`); }"; }
}
interface iA { void foo(iA a); }
class A : iA
{
void foo(A a) { writeln("Specific"); }
//mixin(B);
mixin C; // doesn't work, use line above, does not insert
generic foo
}
void main()
{
iA a = new A;
a.foo(a);
(cast(A)a).foo(cast(A)a);
(cast(A)a).foo(a); // line doesn't work when using mixin
template because the generic foo does not exist
}
This seems like a bug to me but maybe that's how mixin templates
work? If so is there any way to make them insert the code
regardless if it thinks they are the same? (they are not in this
case and I need to use them to reduce redundancy)
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