The relationship of invariants and alias this
Steven Schveighoffer via Digitalmars-d
digitalmars-d at puremagic.com
Tue Nov 11 05:11:54 PST 2014
On 11/11/14 6:48 AM, ZombineDev wrote:
> AFAIU, even if you had a getter in the alias this:
>
> ---
> import std.stdio;
>
> struct ValueRestrictedInteger(int lowerBound, int upperBound) {
> int value;
> auto ref get() { return value; }
> alias get this;
>
> this (int rhs) { value = rhs; }
>
> invariant() {
> assert (value >= lowerBound && value <= upperBound);
> }
>
> void forDemonstrationOnly() {}
> }
> ---
>
> It would still not work:
>
> ---
> unittest {
> ValueRestrictedInteger!(0, 100) x = 0;
>
> x -= 100; //is probably lowered to something like this:
> // 1) invariant();
> // 2) int* __temp = &x.value; // this is what get() does
> // 3) invariant();
> // 4) *__temp = *temp - 100;
>
> //...
> }
> ---
>
> Obviously, 4) will not trigger the invariant because it doesn't call any
> public functions.
Correct, the only real solution is to wrap with the actual operators and
opDispatch.
-Steve
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