splitter overload with terminator predicate requires forward range

[Luís Marques via Digitalmars-d]

The documentation for one of the overloads of 
std.algorithm.splitter claims to require an input range in the 
Parameters section, and a forward range in the function signature 
(template constraint) section:

     auto splitter(alias isTerminator, Range)(Range input) if 
(isForwardRange!Range && 
is(typeof(unaryFun!isTerminator(input.front))));

     Parameters:
     isTerminator	The predicate for deciding where to split the 
range.
     Range input	The input range to be split.

     Returns:
     An input range of the subranges of elements between 
separators. If input is a forward range or bidirectional range, 
the returned range will be likewise

Is this a documentation bug? In any case, I would like to use 
this variant of splitter (a range and a predicate), but I only 
have an input range (because of `tee`) and the template 
constraint rejects that, so changing that requirement would be 
nice.