readln() doesn't stop to read the input.

[Steven Schveighoffer via Digitalmars-d]

On 3/27/15 4:22 AM, tcak wrote:
> On Friday, 27 March 2015 at 05:17:03 UTC, jonaspm wrote:
>> but readln(p); isn't supposed to read input and store it into p?
>
> Nope. Parameter is terminator character. Read string is returned from
> the function. So, it would be like:
>
> string p = readln();

readln has an overload that looks like this:

size_t readln(C)(ref C[] buf, dchar terminator = '\x0a') if 
(isSomeChar!C && is(Unqual!C == C) && !is(C == enum));

Which is what the OP is using (possibly, he never defines p and q).

As for the error, assuming you have proper buffer types for p and q, it 
appears that your stdin is closed somehow. I think this is likely an 
environmental issue. Please post the full code and describe the 
environment if you need more help.

Your code works fine for me on OSX:

import std.stdio;
import std.string;

void main()
{
     char[] p;
     char[] q;
     write("Write p: ");
     readln(p);
     p = chomp(p);
     writeln("Write q: ");
     readln(q);
     q = chomp(q);

     writeln(p, " ", q);
}

RUN:

Write p: adb;lna;lhiser
Write q:
slisieleru
adb;lna;lhiser slisieleru

-Steve