iota and BigInt

Russel Winder via Digitalmars-d digitalmars-d at puremagic.com
Sat May 9 10:09:18 PDT 2015


It appears that someone fixed 2.067 so that BigInts are integral so
that iota can be used with them. This is good. However if I call:

        iota(begin, end)

where begin and end are immutable(BigInt) then it fails. Is this as it
should be or is this a bug?

-- 
Russel.
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Dr Russel Winder      t: +44 20 7585 2200   voip: sip:russel.winder at ekiga.net
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