how to do iota(0,256) with ubytes ? (cf need for iotaInclusive)

[Timon Gehr via Digitalmars-d]

On 10/12/2015 11:52 PM, Jacques Müller wrote:
> On Monday, 12 October 2015 at 20:51:40 UTC, Nordlöw wrote:
>> On Monday, 12 October 2015 at 20:39:11 UTC, Andrei Alexandrescu wrote:
>>>> Alexandrescu wrote:
>>>>> We can add iota!T() with no arguments that spans the entire range of T
>>>>> (integral). -- Andrei
>>
>> From a quick glance I couldn't find a way to reuse the existing
>> overloads. Can anybody come with a reusing solution?
>
> Wouldn't it be enough changing the overload
>
> auto iota(E)(E end)
>
> to
>
> auto iota(E)(E end = E.max)
>
> ?
>

No.

import std.range;
writeln(iota(byte.max));

starts at 0
  |
  v
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19,
20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37,
38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55,
56, 57, 58, 59, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 70, 71, 72, 73,
74, 75, 76, 77, 78, 79, 80, 81, 82, 83, 84, 85, 86, 87, 88, 89, 90, 91,
92, 93, 94, 95, 96, 97, 98, 99, 100, 101, 102, 103, 104, 105, 106, 107,
108, 109, 110, 111, 112, 113, 114, 115, 116, 117, 118, 119, 120, 121,
122, 123, 124, 125, 126]
                      ^
                      |
                ends before 127