How is std.regex.replaceAllInto more efficient?

Shriramana Sharma via Digitalmars-d digitalmars-d at puremagic.com
Fri Oct 16 08:23:12 PDT 2015


Dmitry Olshansky wrote:

> No. Conceptually replace does replaceInto but creates a new appender
> each time. This is the overhead replaceInto means to avoid.

That's much clear now, thanks!

-- 
Shriramana Sharma, Penguin #395953


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