How is std.regex.replaceAllInto more efficient?

[Dmitry Olshansky via Digitalmars-d]

On 16-Oct-2015 18:23, Shriramana Sharma wrote:
> Dmitry Olshansky wrote:
>
>> No. Conceptually replace does replaceInto but creates a new appender
>> each time. This is the overhead replaceInto means to avoid.
>
> That's much clear now, thanks!
>

Feel free to improve on the examples, I'd gladly pull such patches.

-- 
Dmitry Olshansky