How to spawn a thread within method

[John Colvin via Digitalmars-d]

On Thursday, 11 August 2016 at 12:09:37 UTC, eugene wrote:
> Hello, everyone,
> i'm testing my luck with this code, but it does not work. How 
> to make it work?
>
> module test;
>
> import std.stdio, std.concurrency, std.variant;
>
> class Test {
>     public:
> 	void run()
> 	{
>             auto tid = spawn(&this.foo); // is it possible to 
> do so?
>
> 	    foreach (i; 0 .. 10)
> 	        tid.send(i);
> 	    tid.send(1.0f);
> 	    tid.send("hello");
> 	    tid.send(thisTid);
> 	
> 	    receive((int x) => writeln("Main thread received message: 
> ", x));
> 	}
>
>     private:
> 	void foo()
> 	{
> 	    bool cont = true;
> 		
> 	    while (cont)
> 	    {
> 	        receive(
> 	            (int msg) => writeln("int received: ", msg),
> 	            (Tid sender) { cont = false; sender.send(-1); },
> 	            (Variant v) => writeln("huh?")
> 	        );
> 	    }
> 	}
> }
>
> void main()
> {
>     Test t = new Test();
>     t.run();
> }

I think what's happening is that you're implicitly sharing the 
"this" pointer of the class, which isn't allowed. Change foo to 
static and it compiles.

For some reason it segfaults on dpaste: 
https://dpaste.dzfl.pl/feaa2b883e5b   but it runs fine on my 
machine.