inout delegate
Nicholas Wilson via Digitalmars-d
digitalmars-d at puremagic.com
Sat Oct 8 21:57:27 PDT 2016
On Sunday, 2 October 2016 at 09:55:26 UTC, Manu wrote:
> Can someone explain this to me?
>
> class Test
> {
> inout(int) f() inout { return 10; }
>
> void t()
> {
> f(); // calls fine with mutable 'this'
> auto d = &this.f; // error : inout method Test.f is not
> callable
> using a mutable this
> d();
> }
> }
>
> That error message seems very unhelpful, and it's not true. Of
> course an inout method is callable with a mutable 'this'...
>
> I suspect that the problem is the type for the delegate;
> "inout(int)
> delegate()" doesn't leave anything for the type system to
> resolve the
> inout with.
> I guess the expectation is that this delegate has it's
> inout-ness
> resolved when you capture the delegate:
> is(typeof(&this.f) == int delegate())
> Or if 'this' were const:
> is(typeof(&this.f) == const(int) delegate())
>
> But I get this unhelpful error instead.
>
> What's the story here?
That doesn't compile for me (using ad4a81b), but I get a
different error message with an accompanying main
void main()
{
const ct = new Test();
ct.t();
auto at = new Test();
at.t();
immutable it = new Test();
it.t();
}
Error: mutable method Test.t is not callable using a
(const|immutable) object
Note t, not f.
Making t inout fixes this.
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