Why do "const inout" and "const inout shared" exist?

[Andrei Alexandrescu via Digitalmars-d]

On 07/02/2017 09:49 AM, Andrei Alexandrescu wrote:
> On 07/02/2017 09:48 AM, Andrei Alexandrescu wrote:
>>      *p = 42; // should be a shared write, it's not
> 
> I meant:
> 
>      p = new int; // should be a shared write, it's not

Dognabbit. No, I meant the previous one! The pointer itself is private 
to gun. -- Andrei