Should out/ref parameters require the caller to specify out/ref like in C#?

[Stanislav Blinov via Digitalmars-d]

On Sunday, 28 May 2017 at 22:03:48 UTC, Stefan Koch wrote:
> On Sunday, 28 May 2017 at 17:54:30 UTC, WebFreak001 wrote:
>> Imagine you wrote a function
>>
>> void foo(ref int a) {
>>   if (std.random.uniform(0, 10) == 0)
>>     a = 0;
>>   // Actual code doing something
>> }
>>
>> [...]
>
> Syntax wise we could force you to say foo(&something).
> Which fits perfectly in the existing pointer syntax.

No it does not, because then this becomes ambiguous:

foo(ref int a);
foo(int* b);

...and furthermore, what would we do with this:

void foo1(T)(auto ref T a) { foo2(a); }
void foo2(T)(auto ref T a) { /*...*/ }

?