Should out/ref parameters require the caller to specify out/ref like in C#?

[Dukc via Digitalmars-d]

On Monday, 29 May 2017 at 07:46:07 UTC, Stanislav Blinov wrote:
> On Monday, 29 May 2017 at 07:39:40 UTC, Dukc wrote:
>
>> [snip]
>
> Explicitly? It is:
>
> import std.stdio;
>
> struct S
> {
>     int v;
> }
>
> void foo(ref S s)
> {
>     writeln("took S by ref: ", s.v);
> }
>
> void foo(S s)
> {
>     writeln("took rvalue S...");
>     foo(s);      // calls ref overload
> }
>
> void main()
> {
>     S s;
>     foo(s);      // calls ref overload
>     foo(S.init); // calls rvalue overload
> }
>
> And for templates we have auto ref.

Of course, I should have noticed one can already do it that way. 
No need for change, then (imo).