`ref T` should be a type!!

[Dein]

On Monday, 1 April 2019 at 01:18:44 UTC, Walter Bright wrote:
> On 3/31/2019 5:35 PM, Rubn wrote:
>> you can literally use it everywhere else you can use a type.
>
> No, you can't. An array of refs won't compile, either.
>
>   void test(int& a[]); // error
>
> A C++ ref can only appear at the top of a type AST, which is 
> unlike any other type. Which exactly matches the only place a 
> storage class can be!

Seriously? You should know as well as I do what that function 
actually translates to:

    void test(int&* const a);

So I ask you now, how do you get a pointer to a reference. Its 
the exact same thing. Not sure if you are trying to just deceive 
me with some syntax sugar in C++ or what.