`acos` returning `-nan`?
timon.gehr at gmx.ch
Sat Nov 23 18:09:43 UTC 2019
On 23.11.19 18:31, Jonathan Levi wrote:
> Any idea why that is and how I could solve it?
> BTW this is the how that number is created: `cos(a.angle)*cos(b.angle) -
You can print the number at a higher precision:
writefln!"%.16f"(failing); // -1.0000000130385160
I.e., it is actually slightly smaller than -1.
You either have to debug your data source or manually clip the value
into the range [-1.0,1.0] before you call acos.
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