More operators inside `is(...)` expressions
schveiguy at gmail.com
Sun Aug 23 22:11:41 UTC 2020
On 8/23/20 5:52 PM, Dennis wrote:
> On Sunday, 23 August 2020 at 21:20:21 UTC, Steven Schveighoffer wrote:
>> What is the cost here? Just use the same AST node for the is
>> expression, and wrap it in a `not` AST node.
> What would `is(int != T, T)` mean? To me it sounds like T should be
> bound to an arbitrary type that's not int, but when you lower it to
> `!is(int == T, T)` it returns false.
I don't get this question at all.
What does that mean anyway? According to the grammar, the `, T` part is
supposed to be template parameters.
And what is wrong with:
static if (is(int != T))
// use T
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