How std.getopt would look with type functions

[Adam D. Ruppe]

On Sunday, 24 May 2020 at 07:06:31 UTC, Stefan Koch wrote:
> Yes but that's no reason to not show how it would look?

getopt(
    arg("whatever", "help", whatever),
    arg("other", other)
);

It is identical to what you wrote except with implicit template 
args. getopt there is still a variadic template, arg is a factory 
function (with two overloads, with and without the help string) 
that returns a templated struct. The getopt is free to static 
assert fail if an argument isn't  of the typeof(arg).

The final arg is either an explicit pointer or a ref argument 
that takes the address internally for the return value.

No fancy feature needed here.