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dchar works but simple solution doesn't.<BR>
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code:<BR>
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char[] chars = "òà";<BR>
chars.canFind('à');<BR>
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It says:<BR>
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Error: cannot implicitly convert expression ("\xc3\xb2\xc3\xa0") of type string to char[]<BR>
Error: template std.algorithm.canFind(alias pred = "a == b",Range,V) if (is(typeof(find!(pred)(range,value)))) does not match any function template declaration<BR>
Error: template std.algorithm.canFind(alias pred = "a == b",Range,V) if (is(typeof(find!(pred)(range,value)))) cannot deduce template function from argument types !()(char[],wchar)<BR>
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Il giorno mar, 22/11/2011 alle 08.49 -0800, Jonathan M Davis ha scritto:
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On Tuesday, November 22, 2011 17:38:36 Andrea Fontana wrote:
> I guess I should use wchar instead of char. :)
Individual characters really should be processed as dchars in the general
case. There's a simple solution here though:
char[] chars = "àèì";
- Jonathan M Davis
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