Frank Benoit wrote:
>> It doesn't break existing once-working code, because the example shown
>> will not compile with 0.164 and earlier compilers.
>
> It does if you had before both:
> void fn( char delegate() ch ){...}
> void fn( char ch ){...}
>
> is now ambiguous for the call, so the only option is to remove the
> second proto.
That's right.