std.string.toUpper() for greek characters
Dmitry Olshansky
dmitry.olsh at gmail.com
Wed Oct 3 13:37:07 PDT 2012
On 03-Oct-12 23:56, Ali Çehreli wrote:
> On 10/03/2012 11:21 AM, Dmitry Olshansky wrote:
> > On 03-Oct-12 21:10, Ali Çehreli wrote:
> >> On 10/03/2012 03:56 AM, Minas wrote:
> [...]
> >>> map['ά'] = 'Ά';
> [...]
> > Glad you showed up!
>
> Why? Do I whine better? :p
>
Well that might be the case :)
But honestly because you pushed for some Unicode support back in the
days. I currently look around to see if there are obviously important
things not covered in my project.
> > One and by far the most useful case is case-insensitive matching.
> > That being said this doesn't and shouldn't involve toLower/toUpper (and
> > on the whole string) anywhere. Not only it's multipass vs single pass
> > but it's also wrong. As a lot of other ASCII-minded carry-overs.
>
> As I have written at other times, there is an experimental
> alphabet-aware string library (unfortunately even the code is in Turkish
> at this time).
>
If we are talking about the order then this is the way to go:
http://unicode.org/reports/tr10/
Looks like it's one of things I haven't to implemented :(
> That library has the following struct for order-comparing alphabet-aware
> strings and characters:
>
> struct Order
> {
> /**
> * Represents comparing characters at their bases.
> *
> * This value indicates that 'a' and 'b' are different. 'C' and 'c'
> * are the same according to this value. This value disregards upper
> * and lower cases.
> */
> int base;
>
> /**
> * Represents comparing characters by their accents.
> *
> * This value indicates that 'a' and 'â' are different. This value
> * disregards upper and lower cases.
> */
> int accent;
>
> /**
> * Represents comparing characters also by their upper and lower
> cases.
> *
> * Lower case letter comes before upper case.
> */
> int cased;
> }
>
> (Of course opCmp() cannot return that type. :( )
>
> The idea is that only the application knows what type of comparison
> makes sense.
So instead library does all of them ? Ouch.. I'm not sure I got the idea.
--
Dmitry Olshansky
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