IFTI Bug

[Derek Parnell]

On Mon, 10 Jul 2006 00:14:36 -0500, Kramer wrote:


> What would I need to do so IFTI would be invoked?

// ------------------
 import std.stdio;

 void main()
 {
     writefln(factorial(2));
 }

 template factorial(T)
 {
    T factorial(T n)
    {
       if (n <= 1)
         return cast(T)1;
       else
         return cast(T)( n * factorial(n-1));
    }
 }
// ------------------

The example you gave at first was using a template to generate a
compile-time literal. To turn that into a template that generates a
function instead, you need to define the function inside the template. If
you give it the same name as the template, IFTI becomes easier to use too.

-- 
Derek
(skype: derek.j.parnell)
Melbourne, Australia
"Down with mediocrity!"
10/07/2006 3:33:48 PM