[Bug 24] Arithmetic operators are allowed on boolean expressions

[Sean Kelly]

Walter Bright wrote:
> "Sean Kelly" <sean at f4.ca> wrote in message 
> news:dur6p8$2ila$1 at digitaldaemon.com...
>>>     bool x5; x5 += true;  // fails because x5+true is int, and int cannot 
>>> be
>>> implicitly converted to bool unless it is 0 or 1
>> bool defaults to false/0, so x5 + true should equal 1, which should not 
>> fail.
> 
> That would be true if x5 is a const, but it isn't, so it doesn't get 
> constant folded. The same applies to the other examples. 

Oh I see.  Makes a lot more sense now :-)


Sean