[Issue 1648] Casting a function literal to void* swallows the function or segfaults

[Derek Parnell]

On Fri, 9 Nov 2007 10:48:15 +1100, Derek Parnell wrote:

 
> I made a slight change to the code and it seems to work.

Another change to make it clearer to read...

------------
import std.stdio;

class Foo {
    alias void delegate()  dg;
    private dg* _funcptr;
    private dg  _func;
    
    void send (dg* func) {
        _funcptr = func;
    }

    void send (dg func) {
        _func = func;
        _funcptr = &_func;
    }

    void execute () {
        (*_funcptr)();
    }

}

void main () {
    Foo foo = new Foo();

    auto func = { writefln("greetings"); };
    foo.send(&func);
    foo.execute();

    foo.send({ writefln("this one is typed"); });
    foo.execute();
}
----------

-- 
Derek
(skype: derek.j.parnell)
Melbourne, Australia
9/11/2007 10:59:25 AM