[Issue 2678] New: for loops are already assumed to terminate
d-bugmail at puremagic.com
d-bugmail at puremagic.com
Fri Feb 20 07:15:40 PST 2009
http://d.puremagic.com/issues/show_bug.cgi?id=2678
Summary: for loops are already assumed to terminate
Product: D
Version: unspecified
Platform: PC
OS/Version: Linux
Status: NEW
Severity: normal
Priority: P2
Component: DMD
AssignedTo: bugzilla at digitalmars.com
ReportedBy: andrei at metalanguage.com
Consider this code compiled with -w:
int main()
{
int i;
for (;; ++i)
{
if (i == 10) return 0;
}
i += 100;
}
This loop never reaches its end. However the compiler does not detect that and
spuriously asks for a return at the end of the function. Worse, if there is
some unreachable code following the loop, it does not recognize that.
All loops that (a) have no termination condition or a nonzero
compile-time-constant termination condition, and (b) do not embed any "break"
statement - should be understood as loops that do not fall through.
Before anyone brings up Turing completeness: I said "nonzero
compile-time-constant termination condition".
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