[Issue 5157] New: thread_joinall() looks like it doesn't actually join all
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Tue Nov 2 20:47:55 PDT 2010
http://d.puremagic.com/issues/show_bug.cgi?id=5157
Summary: thread_joinall() looks like it doesn't actually join
all
Product: D
Version: unspecified
Platform: Other
OS/Version: Linux
Status: NEW
Severity: normal
Priority: P2
Component: druntime
AssignedTo: sean at invisibleduck.org
ReportedBy: jmdavisProg at gmx.com
--- Comment #0 from Jonathan M Davis <jmdavisProg at gmx.com> 2010-11-02 20:46:51 PDT ---
In core.threads, there is a function called thread_joinall() which supposedly
joins all non-daemon threads. At present, it's implementation is
extern (C) void thread_joinAll()
{
while( true )
{
Thread nonDaemon = null;
foreach( t; Thread )
{
if( !t.isDaemon )
{
nonDaemon = t;
break;
}
}
if( nonDaemon is null )
return;
nonDaemon.join();
}
}
Notice that the last if statement _returns_ if the thread is a daemon thread.
That means that the function joins every thread until it finds a single daemon
thread, so it's _not_ going to join all non-daemon threads unless there are no
daemon threads or all of the daemon threads are at the end of the range
generated by opApply(). So, if I understand correctly what the function is
supposed to be doing, it should be something more like this:
extern (C) void thread_joinAll()
{
foreach( t; Thread )
{
if( !t.isDaemon )
t.join();
}
}
This still might have issues though if the list of running threads changes
while thread_joinAll() is running. I think that opApply() will iterate over the
list of threads as they exist when opApply() is called, but if any threads are
joined while opApply() is running (likely because joining a thread causes
another thread to join in addition to the one join() was called on), then you
could get a double-join happening, which would currently result in an exception
being thrown. So, there may also need to be a way to verify that a thread
hasn't been joined before attempting to join it. And of course, some locking
primitives may be necessary to make sure that there aren't any race conditions
in doing so.
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