[Issue 4968] inout is sticky to function return type

[d-bugmail at puremagic.com]

http://d.puremagic.com/issues/show_bug.cgi?id=4968


Steven Schveighoffer <schveiguy at yahoo.com> changed:

           What    |Removed                     |Added
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                 CC|                            |schveiguy at yahoo.com


--- Comment #1 from Steven Schveighoffer <schveiguy at yahoo.com> 2010-10-04 06:06:46 PDT ---
This is a good catch.  Although inout doesn't work currently, so don't expect
much yet.

IMO, this is how the compiler should behave:

void foo(T)(T t)
{
  writeln(typeof(t).stringof);
}

inout(int)
f(inout(int) i)
{
   return i;
}

void main()
{
   int i;
   const int j;
   immutable int k;
   foo(f(i));
   foo(f(j));
   foo(f(k));
}

should print:

int
const(int)
immutable(int)

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