[Issue 6394] template type constraints embedded in the function parameters.

d-bugmail at puremagic.com d-bugmail at puremagic.com
Thu Jul 28 08:49:20 PDT 2011


http://d.puremagic.com/issues/show_bug.cgi?id=6394



--- Comment #1 from Gor Gyolchanyan <gor at boloneum.com> 2011-07-28 08:49:18 PDT ---
Given the code:

---------------

template SomeStruct(Type)
{
    static if(is(Type == struct) || is(Type == class) || is(Type == interface))
        enum StaticStruct = true;
    else
        enum StaticStruct = false;
}

---------------

I suggest a syntax sugar for template functions:

---------------

void f(SomeStruct s)
{
}

---------------

be transformed into:

---------------

void f(Type_0_)(Type_0_ s)
    if(SomeStruct!Type_0_)
{
}

---------------

IF the given type isn't a valid type, it'll search for a template, that takes a
single type and evaluates to a bool and transform the function if the type name
is such a template.

this would greatly increase the readability of generic functions and allow to
avoid creating enormous template constraints, as well as provide a better
diagnostics, like "the type T is not a SomeStruct" or something like that.

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