[Issue 5801] New: Using typeof() in function header breaks ITFI and default template arguments.

d-bugmail at puremagic.com d-bugmail at puremagic.com
Wed Mar 30 15:59:08 PDT 2011


http://d.puremagic.com/issues/show_bug.cgi?id=5801

           Summary: Using typeof() in function header breaks ITFI and
                    default template arguments.
           Product: D
           Version: D2
          Platform: Other
        OS/Version: Mac OS X
            Status: NEW
          Keywords: rejects-valid
          Severity: major
          Priority: P2
         Component: DMD
        AssignedTo: nobody at puremagic.com
        ReportedBy: code at klickverbot.at


--- Comment #0 from klickverbot <code at klickverbot.at> 2011-03-30 15:55:34 PDT ---
The following program compiles (bar uses a default type for T, baz relies on
IFTI):
---
void bar(T = double)(int i) {}
void baz(T)(int i, T t) {}
void main() {
    bar(2);
    baz(3, "baz");
}
---

But if typeof() is used instead of explicitly specifying int, neither calls to
bar and baz work any longer:
---
int a;
void bar(T = double)(typeof(a) i) {}
void baz(T)(typeof(a) i, T t) {}
void main() {
    bar(2);  // Does not compile.
    baz(3, "baz"); // Does not compile.
}
---

The respective error messages are:
Error: template test.bar(T = double) does not match any function template
declaration
Error: template test.bar(T = double) cannot deduce template function from
argument types !()(int)
and
Error: template test.baz(T) does not match any function template declaration
Error: template test.baz(T) cannot deduce template function from argument types
!()(int,string).

If the template parameter is specified explicitly, however, both of the
examples work again:
---
int a;
void bar(T = double)(typeof(a) i) {}
void baz(T)(typeof(a) i, T t) {}
void main() {
    bar!double(2);
    baz!string(3, "baz");
}
---

DMD from Git master at b7133502.

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