[Issue 1528] [tdpl] overloading template and non-template functions
d-bugmail at puremagic.com
d-bugmail at puremagic.com
Wed Feb 27 04:39:14 PST 2013
http://d.puremagic.com/issues/show_bug.cgi?id=1528
monarchdodra at gmail.com changed:
What |Removed |Added
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CC| |monarchdodra at gmail.com
--- Comment #14 from monarchdodra at gmail.com 2013-02-27 04:39:08 PST ---
(In reply to comment #13)
> I have implemented it in accordance with TDPL, and the following behaviour
> results:
>
> // vs deduced parameter + template constraint (2)
> int f6(int a) { return 1; }
> int f6(T)(T b) if (is(T : int)) { return 2; }
>
> void main(){
> static assert(f6(1)==1);
> static assert(f6(1L)==1);
> }
How does that work though, because here, you statically know that 1L will fit
in your int. But what about:
static assert(f6(1L) == 1);
static assert(f6(ulong.max) == 2); // (a) ???
ulong ul = runtime();
static assert(f6(ul) == 2); // (b) ???
How would these resolve?
I am not really comfortable with the fact that a call can statically resolve to
two different functions depending on the static information of the *value* of a
parameter:
int f7(ubyte a) { return 1; }
int f7(T)(T b) if (is(T : int)) { return 2; }
void main(){
static assert(f6(200u)==1); //Calls first
static assert(f6(400u)==2); //Calls second (!?)
//Run-time variable with TDPL-like range knowledge
uint a = 400;
static assert(f6(a) == 2); //Calls second ?
a = 200;
static assert(f6(a) == 1); //But now calls first !?
}
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