[Issue 12386] Allow using derivatives of IFTI'd types in remaining arguments

[d-bugmail at puremagic.com]

https://d.puremagic.com/issues/show_bug.cgi?id=12386



--- Comment #1 from Vladimir Panteleev <thecybershadow at gmail.com> 2014-03-17 07:50:51 EET ---
This doesn't work as one might expect:

void f(T, U=X!T)(T a, U b) {}

U will always be inferred from the type of b, overriding the default.

Valid workaround:

void f(T, U)(T a, U b) if(is(U==X!T)) {}

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