What's the difference between "out" and "inout"?

[Unknown W. Brackets]

There's a big difference:

out initializes the variable to the default initializer.
inout does not change the value passed in.

Example:

import std.stdio;

int foo1(out i)
{
    writefln(i);
}

int foo2(inout i)
{
    writefln(i);
}

int main()
{
    int i;

    i = 5;
    foo1(i);

    i = 5;
    foo2(i);

    return 0;
}

Will output:

0
5

Because in the first case i is set to 0 because it is an int.  Out means 
that the value before the call doesn't matter; with inout it may matter.

-[Unknown]


> Maybe a silly question, but what's the difference bebtween "out" 
> parameters and "inout" parameters?
> For a long time I was under the impression that there's no difference .. 
>  but I'm not sure anymore.