why are Assign Expressions r-values?

[Daniel Keep]

BCS wrote:
> Reply to Daniel,
> 
>> BCS wrote:
>>
>>> fo(void, 1);  // call fo with a temporary variable for i and a temp
>>
>> I'd be tempted to just use
>>
>> foo(0, 1);
>>
>> Since the first argument's going to be re-initialised anyway.  That
>> said, having a way to specify "I don't care what goes here" would be
>> nice.  The problem with using void would be functions like this:
>>
>> void ba(out int* i, inout int j);
>>
>> If you specify the first argument as void, what are you actually
>> saying?
>> Create temporary storage for the first argument, or actually pass
>> void?
> 
> void has no value. Might you be thinking of null?

I could be... I could be.  It's certainly a possibility.  I would like
to think I know what I'm talking about, but clearly that's not true. :P

My excuse is that void *should* be a literal (equal to void.init), and
hence why I was confused.  Not stupid.  Nope.

	-- Daniel

-- 
int getRandomNumber()
{
    return 4; // chosen by fair dice roll.
              // guaranteed to be random.
}

http://xkcd.com/

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