Tango BitArray Initialization
Sean Kelly
sean at f4.ca
Tue Feb 13 00:08:41 PST 2007
kris wrote:
> Bill Baxter wrote:
>> Bill Baxter wrote:
>>
>>> Sean Kelly wrote:
>>>
>>>> Bill Baxter wrote:
>>>>
>>>>> John Reimer wrote:
>>>>>
>>>>>> On Sun, 11 Feb 2007 19:41:48 -0800, Sean Kelly wrote:
>>>>>>
>>>>>
>>>>>> Another simple alternative could employ a static opAssign.
>>>>>>
>>>>>> This would make things much simpler:
>>>>>>
>>>>>> BitArray bitbag = 0b11111000000;
>>>>>>
>>>>>> The value is limited to 64-bits, but at least it's clean and
>>>>>> simple for
>>>>>> those situations where we don't have a long initialization value.
>>>>>> (this would work for hexidecimal value also). For any larger
>>>>>> values we
>>>>>> can use an array literal assignment or something similar.
>>>>>>
>>>>>
>>>>> Does opAssign work that way? I think it has to be done in two lines:
>>>>>
>>>>> BitArray bitbag;
>>>>> bitbag = 0b11111000000;
>>>>>
>>>>> Yes that does seem to be the case. Otherwise you get, bizarrely,
>>>>> the error "no property 'opCall' for type 'Foo'".
>>>>
>>>>
>>>> Oddly, if you make the opCall static, it works.
>>>>
>>>>
>>>> Sean
>>>
>>>
>>> Hmm. Show me how. This and several variations of this that I tried
>>> do not work:
>>>
>>> import std.stdio;
>>> struct Struct
>>> {
>>> static void opAssign(int i) {
>>> val = i;
>>> }
>>> int val = 0;
>>> }
>>>
>>> void main()
>>> {
>>> Struct s = 2;
>>> writefln("S.val=%s", s.val);
>>> }
>>
>>
>> Oh, wait. "if you make the *opCall* static". Weird. This does work:
>>
>> import std.stdio;
>>
>> struct Struct
>> {
>> static Struct opCall(int i) {
>> Struct s;
>> s.val = i;
>> return s;
>> }
>> void opAssign(int i) {
>> val = i;
>> }
>> int val = 0;
>> }
>>
>> void main()
>> {
>> Struct s = 2;
>> writefln("S.val=%s", s.val);
>> }
>>
>> Neat!
>> --bb
>
>
> No opCall needed. Just return the struct from the static opAssign() instead
Oddly, I wasn't able to get static opAssign to work with this syntax.
It seemed to want "BitArray = 0" rather than "BitArray b = 0". I've
modified Tango's BitArray to support:
BitArray b = [0,1,0,1];
b = [1,0,1,0];
which is consistent with how built-in arrays work.
Sean
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