references and function calls

[Derek Parnell]

On Fri, 16 Mar 2007 14:27:14 +0100, Frits van Bommel wrote:

> You seem to have a misunderstanding on the semantics of 'out':

No, I didn't misunderstand. What happened was I wrote quicker than I
thought, and then I didn't review my writing before posting.

You are correct that the result of 'out' parameters is an initialized value
if the called function doesn't do anything to it.

-- 
Derek Parnell
Melbourne, Australia
"Justice for David Hicks!"
skype: derek.j.parnell