Treat a normal function as variadic?

[Robin Allen]

void f0()    {}
void f1(...) {}
void main()
{
	auto pf0 = &f0;
	auto pf1 = &f1;

	writefln(typeid(typeof(pf0)));
	writefln(typeid(typeof(pf1)));
}


The above program shows pf0 and pf1 to have the same type, 'void()*'. 
(Which, incidentally, isn't a type. Shouldn't it be 'void(*)()'?)

The thing is, I can call pf1(64), but not pf0(64) (wrong number of 
arguments), even though pf0 and pf1 should behave identically, having 
the same type.

Basically, I need a way to treat a non-variadic function as if it were 
variadic. I'm asking because I'm writing a scripting language, and I 
want to make normal D functions callable from the script, where the 
number of arguments given isn't known at compile time.