Array out of bounds

[Barry Denton]

Jarrett Billingsley Wrote:

> "Barry Denton" <basse42 at yahoo.com> wrote in message 
> news:fu0hfh$29mq$1 at digitalmars.com...
> > from the examples I  try to do
> >
> > int COUNT = 10000;
> >    char [COUNT][] itemStrings ;
> >    for (int i = 0; i < COUNT; i++) {
> >
> >      itemStrings [i][] = ("item " ~ to!(char[]) (i));
> >
> > 2 problems -does not accept COUNT as the size
> 
> You can't declare a statically-sized array with a non-constant value.  If 
> you know you will always have 10000 values, use:
> 
> const int COUNT = 10000;
> 
> If the number of values can vary at runtime, use a dynamically allocated 
> array instead:
> 
> char[][] itemStrings = new char[][](n, count);
> 
> > and if I use char[10000] its OK but after compiles OK but index out of 
> > bounds error given on itemStrings[][]   line
> 
> You haven't given any size to the second dimension of the array.  You've 
> declared the array reference but haven't actually created an array.
> 
> Maybe you're getting the syntax confused.  The C-style syntax:
> 
> char itemStrings[COUNT][];
> 
> becomes:
> 
> char[][COUNT] itemStrings;
> 
> in D.  Your array:
> 
> char[COUNT][] itemStrings;
> 
> reads as "a dynamic array of statically-sized arrays of length COUNT of 
> int".  You read right-to-left.  It seems you want the other way, 
> char[][COUNT].
> 
> Even then, your loop is still wrong.  You are trying to slice-assign an 
> array that doesn't exist.  Simply take out the slice on the left-hand-side:
> 
> itemStrings[i] = "item " ~ to!(char([])(i);
> 
> And it will fill in itemStrings[i] with the new string.
> 
> 
Thanks !