What does it mean: buffer[0 .. kSize] = input[index .. (index + Size)];

[t0mek]

> It is *exactly* the same (however, a memcpy could be used under the hood), 
> i.e.
> - there is no allocation
> - data will be overwritten
> - an OutOfBounds exception will be thrown if array is not large enough

Thanks!

Regards,
t0mek