passing all writefln arguments
    Bill Baxter 
    dnewsgroup at billbaxter.com
       
    Thu Mar 20 16:27:48 PDT 2008
    
    
  
Saaa wrote:
> Thanks,
> 
> As I think that changing a variable is easier than changing the compiler 
> line I went with:
> 
> const bool DEBUGG=false;
> 
> static if (DEBUGG == true) {
>  alias writefln dWritefln;
> }
> else {
>  void dWritefln(...) {}
> }
I think you can set debug versions inside a file too.  That way you can 
have the best of both worlds.  Turn it on from the command line, or by 
modifying the file.
debug = DEBUGG;
debug(DEBUGG) {
  alias writefln dWritefln;
}
else {
  void dWritefln(...) {}
}
... at least that works with 'version'.  Not sure if it works with debug 
too.  (If it doesn't I'll file a bug about the inconsistency with 
'version'.)
> Will dWritefln(..){} compile to 'nothing'?
 > I mean, will calling dWritefln when DEBUGG=false take no cpu tick 
(does the
 > compiler see that it does nothing)?
Yes.  See thread entitled "debug()" over in digitalmars.D.
digitalmars.com digitalmars.D:66826
digitalmars.com digitalmars.D:66827
But that may only be with -inline.  Not sure what flags Jarrett used 
when he ran the test.
--bb
    
    
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