How to get a function name (string) @ compile time

[Denis Koroskin]

On Mon, 03 Nov 2008 01:59:56 +0300, Daniel Ribeiro Maciel  
<daniel.maciel at gmail.com> wrote:

> How do we get a function name (string) @ compile time?
>
> I need to do stuff like (in C)
>
> #include <stdio.h>
>
> #define HELLO( func ) \
>   printf( "calling " #func "\n" ); \
>   func();
>
> void foo()
> {
> 	printf( "@foo" );
> }
>
> int main()
> {
> 	HELLO( foo );
> 	printf( "\n" );
> }
>
> The output is:
> calling foo
> @foo
>
> Thanks in advance,
> Daniel
>

Just in case you know little D here is the source code, explanation and  
comparison to C++:

import std.stdio; // this is used to import writefln() - a function  
similar to printf (but typesafe)

// this is a template function that takes almost anything (close to C++  
templates and C macros)
void print(alias functionName)()
{
     // stringof is used to take a string representation of the identifier
     writefln("Calling ", functionName.stringof);

     // let's invoke it! This will succeed if functionName is a function,  
pointer to function,
     // delegate or an object that have overloaded opCall() (similar to C++  
operator())
     functionName();
}

void foo()
{
     writefln("@foo"); // same as printf("@foo);
}

void main()
{
     // foo is a global (free) function. it is passed to the template  
function.
     // In C++ you would do print<foo>(); (but C++ doesn't support  
specializing
     // templates with functions nor does it have .stringof)
     print!(foo);
}