Array-initialization
torhu
no at spam.invalid
Thu Oct 9 16:50:31 PDT 2008
Hendrik Renken wrote:
> Hi,
>
> i have a question regarding array-initialization.
>
>
> consider:
>
> struct STRUCT
> {
> byte[] data;
> }
>
>
> STRUCT foo(byte[] myData)
> {
> STRUCT* s = new STRUCT(myData);
> }
>
>
> do i now create a struct with an array on the heap and then drop the
> array and assign to the array-pointer the array "myData"? If yes, how
> can i avoid the creation and deletion of the array "data" in the first
> place? Am i right, that the variable "data" only holds a pointer to the
> real array?
"data" is a dynamic array reference, so STRUCT is really just this:
struct STRUCT
{
size_t length;
byte* ptr;
}
So "data" is just a number of elements and a pointer to the first one.
When you do "new STRUCT(myData)", you're only allocating room for that.
There's no room for array contents allocated, just the reference.
If you do writeln(STRUCT.sizeof); it will always say 8 on a 32-bit
system, same goes for data.sizeof.
Your example should probably look like this, as there's no point in heap
allocating small structs:
STRUCT foo(byte[] myData)
{
STRUCT s = STRUCT(myData);
}
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