Is there a way to remove the requirement for parenthesis?
    Charles Hixson 
    charleshixsn at earthlink.net
       
    Wed Jan 21 09:24:01 PST 2009
    
    
  
In this test I'm trying to emulate how I want a typedef to act, but I 
run into a problem:
import   std.stdio;
struct   BlockNum
{  uint   value;
    uint   opCast()   {   return   value;   }
    void   opAssign (uint val)   {   value = val;   }
    uint   opCall()   {   return   value;   }
}
void   main()
{  BlockNum   test;
    test   =   42;
    uint   tst2   =   test();  // <<== if I don't have the parenthesis I
                               //    get a compiler error (cast
                               //    required).
           //  kfile.d(15): Error: cannot implicitly convert expression
           //          (test) of type BlockNum to uint
    writef ("tst2 = %d\n", tst2);
}
It seemed to me as if the parens shouldn't be required here, but I seem 
mistaken.  Which leads to ugly code.  Is there a way around this?
    
    
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