Forward references and more
Steven Schveighoffer
schveiguy at yahoo.com
Mon Oct 12 05:31:26 PDT 2009
On Mon, 12 Oct 2009 05:26:58 -0400, bearophile <bearophileHUGS at lycos.com>
wrote:
> What's wrong with this code?
>
> struct MemoryPool(T) {
> alias T[100_000 / T.sizeof] Chunk;
> Chunk*[] chunks;
> }
> struct Foo {
> int x;
> MemoryPool!(Foo) pool;
> }
> void main() {}
>
> It prints "Error: struct problem.Foo no size yet for forward reference".
> T.sizeof must be 8 in all cases.
>
>
> So I have tried to pull pool out:
>
> struct MemoryPool(T) {
> alias T[100_000 / T.sizeof] Chunk;
> Chunk*[] chunks;
> }
> MemoryPool!(Foo) pool;
> struct Foo {
> int x;
> // here uses pool
> }
> void main() {}
>
> But there's a problem still:
> Error: struct problem2.Foo no size yet for forward reference
>
> To compile the code I have to move pool forward still:
>
> struct MemoryPool(T) {
> alias T[100_000 / T.sizeof] Chunk;
> Chunk*[] chunks;
> }
> struct Foo {
> int x;
> // here uses pool
> }
> MemoryPool!(Foo) pool;
> void main() {}
>
> When possible it's better to avoid global variables. To avoid the global
> variable I may pass the instance pool to Foo. But to do this Foo has to
> become a struct template. But I am not sure how I can do this.
> Do you have any comments or suggestions?
It looks strange what you are doing. A Foo can have a memory pool of a
lot of Foo's? Do you mean to make the memory pool static? I think that
might work.
I think the main problem is you are defining MemoryPool!(Foo).Chunk which
specifically needs to know the size of Foo before Foo is completely
declared.
It's like you are doing this:
struct X
{
X x;
}
Which clearly is incorrect.
-Steve
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