String literal arguments
Yao G.
nospamyaoltzin at gmail.com
Tue Apr 6 22:23:12 PDT 2010
Hello.
I'm trying to learn more of D templates, but I'm stuck with an issue I
cannot resolve. Well, actually, I don't know if this is even allowed, and
that's why I'm posting here. Suppose I have a function declared like this:
---
import std.traits;
void foo(T...)(T args) if( isSomeString!(T[0]) )
{
/// Some random code.
}
---
and then I call it:
---
auto first = 1;
auto second = 2;
foo( "Hello World", first, second );
---
You can notice that the first argument is a string literal. What I want to
know is: If a function argument is declared as a string literal, it can be
accessed at compile time? And if the answer is yes, how can I do it?.
Currently, if within the function body I attempt this:
---
// Silly example. Actually I have something a little more complex.
static if( args[0].length > 0 ) {
// ...
}
---
The compiler complains that the above code cannot be evaluated at C.T.
Even if the argument is a string literal. The only way that I can make
this work is if I rewrite the function to:
---
void foo(string str, T...)(T args) if( isSomeString!(T[0]) )
{
// This works well
static if( str.length > 0 ) {
// ...
}
}
---
But then I would have to write the function calls like this:
---
foo!("Hello World")(first, second);
---
And honestly, I like more the former way. Not a big deal if you look
objectively, but well, I cannot resist to bikeshed myself.
I hope to make some sense. Cheers!
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