Initializing static arrays without specifying size

[Philippe Sigaud]

On Mon, Aug 2, 2010 at 00:28, Ziad <hatahet at gmail.com> wrote:

>
> If I want a static array:
>
> int[5] a = [1, 2, 3, 4, 5];
>
> I'd have to specify the size in advance (5 in this case), which
> means that adding extra elements later on would require that the
> size be update.
>
> Is there a way to let the compiler automatically determine the size
> based on the argument list?
>

Would a template-based solution be OK?

import std.stdio, std.traits;

CommonType!T[T.length] staticArray(T...)(T vals)
    if ((T.length > 0) && is(CommonType!T))
{
    return [vals];
}

void main()
{
    auto a = staticArray(0,1,2,3,4);
    writeln(typeof(a).stringof); // int[5u]

    auto b = staticArray(3.14);
    writeln(typeof(b).stringof); // double[1u]

    auto mixed = staticArray(0,1,2,3,4, 3.14);
    writeln(typeof(mixed).stringof);  // double[6u]
}


Philippe
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