inout based on this reference?

[Simen kjaeraas]

Steven Schveighoffer <schveiguy at yahoo.com> wrote:
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> On Sun, 29 Aug 2010 17:36:24 -0400, Simen kjaeraas  
> <simen.kjaras at gmail.com> wrote:
>
>> Is it possible to make a function return dependent upon the constancy  
>> of the this reference?
>>
>> i.e. this:
>>
>> struct foo {
>>     int n;
>>     inout( ref int ) getn( ) inout {
>>         return n;
>>     }
>> }
>
> Yes.  That is the bread-and-butter usage for inout.
>
> Although inout is currently horribly broken.

So horribly broken that example does not work at all, or is that just me?

This is my code, verbatim:

//////////////////////////
module foo;

struct bar {
     int n;
     ref inout( int ) getN( ) inout {
         return n;
     }
}

void main( ) {
}
//////////////////////////

And it gives this message:

foo.d(5): Error: inout on return means inout must be on a parameter as
well for inout inout(int)()

-- 
Simen