lazy variables cannot be lvalues - why?

[Adam Cigánek]

Hello,

why is the following code illegal?


  import std.stdio;

  void delegate() fun;

  void capture(lazy void f) {
    fun = &f;
  }

  void main() {
    capture(writeln("hello"));
    fun();
  }


It says "Error: lazy variables cannot be lvalues", pointing to the
"fun = &f" line.

It can be worked around by rewriting it like this:

void capture(lazy void f) {
  fun = delegate void() { f(); };
}

So it's not big deal, just a minor inconvenience. But still, why is it
illegal? According to the docs
(http://www.digitalmars.com/d/2.0/lazy-evaluation.html), lazy
expressions are implicitly converted to delegates, so it seems to me
that it should work.

adam.